. Find the sum of 30 consecutive odd numbers of an A.P which the last term is 127.
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a = 1
d= 2
An = 127
An = a + (n-1)d
127 = 1 + (n -1) 2
126= (n -1)2
n-1 = 126/2
n -1 = 63
n = 64
Sn = n/2{ 2a + (n -1) d}
= 32 {2 + 63* 2}
= 32 *128
= 4096 ans
d= 2
An = 127
An = a + (n-1)d
127 = 1 + (n -1) 2
126= (n -1)2
n-1 = 126/2
n -1 = 63
n = 64
Sn = n/2{ 2a + (n -1) d}
= 32 {2 + 63* 2}
= 32 *128
= 4096 ans
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