Find the sum of 47°28'55" and 20°36'52"
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(a) 137 and – 354
(b) – 52 and 52
(c) – 312, 39 and 192
(d) – 50, – 200 and 300
Solution 4
a) 137 and – 354
= 137 + (-354)
= -217
b) – 52 and 52
= -52 + 52
= 0
c) – 312, 39 and 192
= -312 + 39 + 192
= -81
d) – 50, – 200 and 300
= -50 + (-200) + (300)
= 50
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