find the sum of (4a+b-2c) and (3b+2a+5c)
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Answered by
1
hey friend
here is ur answer
sum = 4a + b -2c + 3b + 2a + 5c
=4a + 2a + b + 3b + 5c - 2c
=6a + 4b + 3c
hope it helps
here is ur answer
sum = 4a + b -2c + 3b + 2a + 5c
=4a + 2a + b + 3b + 5c - 2c
=6a + 4b + 3c
hope it helps
shansalgaonkarp6hsr3:
thank you very much ...
Answered by
4
Heya !!!
This is your sum.
Given :
(4a+b-2c) and (3b+2a+5c)
Arranging according to the similar terms..
4a + b - 2c
2a + 3b + 5c
------------------
6a + 4b + 3c
(When (+) and (-) are added, then we subtract the smaller digit from larger, and put the sign of larger digit in the result)
Hence, the answer is 6a + 4b + 3c.
Note : Please look at picture for easy understanding.
Hope It Helps
This is your sum.
Given :
(4a+b-2c) and (3b+2a+5c)
Arranging according to the similar terms..
4a + b - 2c
2a + 3b + 5c
------------------
6a + 4b + 3c
(When (+) and (-) are added, then we subtract the smaller digit from larger, and put the sign of larger digit in the result)
Hence, the answer is 6a + 4b + 3c.
Note : Please look at picture for easy understanding.
Hope It Helps
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