find the value of k in the given polynomial
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as the quotient is (x+1)
by factor theorem
x+1 = 0
x= -1
P(-1) = 0
K^2018 - 2K(-1) + 1 = 0
So we can do it only by hit and trial method
so i am assuming the value of k = -1
and we know that
k^2018 - 2k(-1) +1 = 0
k^2018 +2k +1 = 0
putting -1 in place of k
-1^2018 +2(-1) +1 = 0
1-2+1 = 0 (even power of 1 is always 1)
0 = 0
L.H.S = R.H.S.
So (-1) satisfies our equation
so k = (-1)
by factor theorem
x+1 = 0
x= -1
P(-1) = 0
K^2018 - 2K(-1) + 1 = 0
So we can do it only by hit and trial method
so i am assuming the value of k = -1
and we know that
k^2018 - 2k(-1) +1 = 0
k^2018 +2k +1 = 0
putting -1 in place of k
-1^2018 +2(-1) +1 = 0
1-2+1 = 0 (even power of 1 is always 1)
0 = 0
L.H.S = R.H.S.
So (-1) satisfies our equation
so k = (-1)
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