find the sum of 4A.M's between 3and -7
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Answer:-7;,a1,a2,a3,a4,3
T6=3
a+5d=3
-7+5d=3
5d=10
d=2
a1=a+d=-7+2=-5
a2=-3
a3=-1
a4=1
Sum of 4 AM=-8
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