Math, asked by flor23, 6 months ago

find the sum of 9x squared + 8 x -2,5 x squared + 24x -25, and negative 4x squared + 16x + 12​

Answers

Answered by spacelover123
7

First Possible Question

Find the sum of (9x)² + 8x - 2, (5x)² + 24x - 25 and (-4x)² + 16x + 12

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Answer

⇒ (9x)² + 8x - 2 + (5x)² + 24x - 25 + (-4x)² + 16x + 12

Simply the squared values.

⇒ 81x² + 8x - 2 + 25x² + 24x - 25 - 16x² + 16x + 12

Combine Like Terms.

⇒ 81x² + 25x² - 16x² + 8x + 24x + 16x - 2 - 25 + 12

Add and Subtract Accordingly.

⇒ 106x² - 16x² + 48x + 12 - 2 - 25

⇒ 106x² - 16x + 48x - 15

∴ (9x)² + 8x - 2 + (5x)² + 24x - 25 + (-4x)² + 16x + 12 = 106x² - 16x + 48x - 15

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Second Possible Question

Find the sum of 9x² + 8x - 2, 5x² + 24x - 25 and -4x² + 16x + 12

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Answer

⇒ 9x² + 8x - 2 + 5x² + 24x - 25 - 4x² + 16x + 12

Combine Like terms

⇒ 9x² + 5x² - 4x² + 8x + 24x + 16x - 2 - 25 + 12

Add and Subtract Accordingly.

⇒ 14x² - 4x² + 48x + 12 - 2 - 25

⇒ 10x² + 48x - 15

∴ 9x² + 8x - 2 + 5x² + 24x - 25 - 4x² + 16x + 12 = 10x² + 48x - 15

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