Question

find the sum of a²+3ab-4b² and 9a²-6ab+2b² subtract a²+6ab+4b²​



please anyone send answer fast

Answer 1

Answer:

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Step-by-step explanation:

given algebraic expression are : 4a² + 5b² + 6ab , 3ab , 6a² - 2b² , 4b² - 5ab;

now adding all expressions ;[horizontal method ]

= (4a² + 5b² + 6ab) + 3ab + ( 6a² - 2b² ) + (4b² - 5ab)

= (4a² + 6a² ) + (5b² - 2b² + 4b² ) + (6ab + 3ab - 5ab)

= 10a² + 7b² + 4ab

add all expressions [vertical method ]

4a² + 5b² + 6ab

+ 3ab

+6a² - 2b²

+ 4b² - 5ab

---------------------------------------------------------

10a² + 7b² + 4ab

yeah, we get the same answer with both methods

Answer 2

Answer:

(a² + 3ab -4b²) + (9a²- 6ab + 2b²) - ( a² + 6ab +

4b²)

And Ans is 9a² - 9ab - 6b²

Step-by-step explanation:

a² + 3ab - 4b²

+9a² - 6ab + 2b²

= 10a² - 3ab - 2b²

10a² - 3ab - 2b²

+ a² + 6ab + 4b²

- - -

= 9a² - 9ab - 6b²