Question

Find the sum of additive inverse and multiplicative inverse ​

Answer 1

Answer:

The sum of the additive inverse and multiplicative inverse of a number is equal to the product of -1, the number's successor and and the number's predecessor divided by the number.

Step-by-step explanation:

Let the number be x.

Additive inverse of x is -x.

Multiplicative Inverse is 1/x.

$-x+\frac{1}{x}=\frac{-x^2+1}{x}\\\\=\frac{(1+x)(1-x)}{x}\\\\=\frac{-1(x+1)(x-1)}{x}$

Thus, the sum of the additive inverse and multiplicative inverse of a number is equal to the product of its successor, predecessor and -1 upon the number.

Hope it helps!

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Answer 2

Answer:

As we Know additive inverse is change of positive negative sign and multiplicative inverse is reciprocal

So let the no. be (a)

Step-by-step explanation:

So

Additve inverse = (-a)

Multiplicative Inverse= 1/a

=   1/a+ (-a)  take Lcm

(1-a²)/a

hope it helps