Question

Find the sum of all 2 digit multiples of 8

please answer step by step

Answer 1

Step-by-step explanation:

2+6=8

1+7=8

4+4=8

3+5=8

8+0=8

Answer 2

Step-by-step explanation:

First two-digit multiple of 4 will be 12.

Last two-digit multiple of 4 will be 96.

Here the series will be 12,16,20,.....,96

We know t

n

=a+(n−1)d

Thus 96=12+(n−1)4

⇒84=4n−4

⇒4n=88

⇒n=22

Sum=

2

22

(12+96)=1188

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