Find the sum of all 2 digit number when divided by 3 leaves a leaves 1 as remainder
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the 2 digit numbers which leave a remainder 1 when divided by 3 are in such an ap.... 10,13,16......97
an=a+(n-1)d
97=10+(n-1)d
87=3n-3
84=3n
28=n
Sn=n/2(a+l)
Sn=14(10+97)
Sn=14(107)
Sn=1498.........
Hope it helps u............
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