Find the sum of all 2 digit numbers which leave remainder 2 when devided by 5
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Sum of 'n' terms = n(2a + (n - 1)d)/2
Therefore,
Answer = 98910
This is sum of all three digit numbers.
Thank You.
Therefore,
Answer = 98910
This is sum of all three digit numbers.
Thank You.
Attachments:
garimagill12:
For 2 digit no.
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