find the sum of all 2 digits number divisiable by 5
Answers
Answered by
1
Step-by-step explanation:
So a+(n-1)d=95. 10+(n-1)*5=95,then n=18. Required sum=n/2(a+l)=18/2(10+95)=945.
Answered by
2
Step-by-step explanation:
Required numbers are 10,15,20,25,......96
This is an A.P. in which a=10,d=5 and l=95
tn =95 ⇒ a+(n−1)d=95
⇒ 10+(n−1)×5=95
⇒ (n−1)×5=85
⇒ (n−1)=17
⇒ n=18
∴ Required sum= n/2(a+l) = 18/2 ×(10+95) = (95×105) = 945.
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