Question

find the sum of all 2 digits number divisiable by 5​

Answer 1

Step-by-step explanation:

So a+(n-1)d=95. 10+(n-1)*5=95,then n=18. Required sum=n/2(a+l)=18/2(10+95)=945.

Answer 2

Step-by-step explanation:

Required numbers are 10,15,20,25,......96

This is an A.P. in which a=10,d=5 and l=95

tn =95 ⇒ a+(n−1)d=95

⇒ 10+(n−1)×5=95

⇒ (n−1)×5=85

⇒ (n−1)=17

⇒ n=18

∴ Required sum= n/2(a+l) = 18/2 ×(10+95) = (95×105) = 945.

MARK AS BRAINILIEST.