Question

find the sum of all 3 digit number which are divisible of three​

Answer 1

Answer:

Your answer is 165150...........

Step-by-step explanation:

The three digit numbers which are divisible by three form an AP.

First term=lowest three digit number divisible by 3=a = 102

Common difference=d=3

Greatest three digit number divisible by 3=999

Let 999 be the nth term of the AP

=>a..n=999

=>a+(n-1)d=999

=>102+(n-1)3=999

=>102+3n-3=999

=>99+3n=999

=>3n=999-99

=>3n=900

=>n=300

Sum of all three digit numbers divisible by 3=S..n

=(n/2)(a+a..n)

=(300/2)(102+999)

=150×1101

=165150________(ans)

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