find the sum of all even numbers 101to999?
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Hi friend,
Sum of first 'n' even integers = n(n+1)
sum of all even intergers between 101 and 999
= Sum of all even integers between 1 and 9999- sum of all even integers between 1 and 101
= 9999(9999+1) - 101(101+1)
= 9999(10000)-101(102)
=99990000-10302=99979698
HOPE THIS HELPS YOU:-))
Sum of first 'n' even integers = n(n+1)
sum of all even intergers between 101 and 999
= Sum of all even integers between 1 and 9999- sum of all even integers between 1 and 101
= 9999(9999+1) - 101(101+1)
= 9999(10000)-101(102)
=99990000-10302=99979698
HOPE THIS HELPS YOU:-))
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