find the sum of all integers between 10 &50 which leave remainder 2 .when divided by 3
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Sum= 427
Step-by-step explanation:
AP is
11,14,17,.......,50
a=11
d=3
l=50
l=a+(n-1)d
50=11(n-1)3
39/3=n-1
13=n-1
n=14
Sum=n/2(a+l)
= 14/2(11 + 50)
= 7 (61)
= 427
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