Question

find the sum of all integers between 100 and 500 which are divisible by 3 ?


*class 10th*​

Answer 1

Step-by-step explanation:

First term is 102 and Last term is 498

498 = 102 + (n-1)3

n = 133

=> Sn = n/2(a+l)

= 133/2(600)

= 300*133

= 39900