find the sum of all integers between 35 and find 100 which are divisible by 3 and 4
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Answered by
0
Answer:
432
Step-by-step explanation:
Numbers divisible by 3 and 4 between 35 and 100 are the multiples of 12 (3*4) : 36, 48, 60, 72, 84, 96
=12*1+12*2+12*3+12*4+12*5+12*6+12*7+12*8
=12(1+2+3+4+5+6+7+8)
=12(36)
=432
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