find the sum of all integers between 84 and 719 which are multiple of 5
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harshgori
Harshgori Expert
hey friend⭐
........
here is ur answer...
TO FIND :-the sum of multiples of 5 between 84 and 719
SOLUTION :-
multiples of 5 btw 84 and 719 forms A.P
abd in this AP WE HAVE:-
a = 85
d = 5
an or last term = 715
n = ?
sum of n terms = ?
so firt we habe to find no. of terms
so an = a+ (n-1) * d
→715 = 85 + (n-1) *5
→715 - 85 = (n-1) *5
→630/5 = n-1
→126+1 = n
no. of multiples of 5 btw 84 and 719= 127
so sum of multiples = n/2*(a+l)
→sum of multiples = 127/2* (85 +715)
→sum of multiples = 127/2 *800
→sum of multiples= 127*400
→sum of multiples= 50800
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HOPE IT HELPS..
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Answer:
The sum of all integers between 84 and 719, which are multiples of 5 is 50800.
Step-by-step explanation:
Given :
Integers between 84 and 719, which are multiples of 5 are 85, 90,95 ,...... 715
Here,
a = 85, d = 5, an( l) = 715
By using the formula ,an = a + (n - 1)d
715 = 85 + (n -1)5
715 - 85 = 5(n -1)
630 = 5(n -1)
n -1 = 630/5
n -1 = 126
n = 126 + 1
n = 127
By using the formula ,Sum of nth terms , Sn = n/2 [a + l]
⇒ S127 = 127/2 (a + l)
⇒ S127 = 127/2 (85 + 715)
⇒ S127 = 127/2 (800)
⇒ S127 = 127 × 400
⇒ S127 = 50800
Hence, the sum of all integers between 84 and 719, which are multiples of 5 is 50800.
HOPE THIS ANSWER WILL HELP YOU….