Find the sum of all integers between 92 and 786 which are multiples of 9
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Answered by
28
In between 92 and 786, The first multiple of 9 is 99 and the last multiple is 783.
Therefore the AP is 99, 108, ...... 783
a = 99, l = 783, d = 9
l = a + (n - 1)d
783 = 99 + (n-1)9
By solving, you get, n = 77
Therefore, the sum = n [ a + l ] /2
= 77 [ 99 + 783 ] / 2
= 77 ( 882 ) /2
= 33957
Therefore the AP is 99, 108, ...... 783
a = 99, l = 783, d = 9
l = a + (n - 1)d
783 = 99 + (n-1)9
By solving, you get, n = 77
Therefore, the sum = n [ a + l ] /2
= 77 [ 99 + 783 ] / 2
= 77 ( 882 ) /2
= 33957
Answered by
1
Answer:
33957 is the sum of multiple of 09 lying between 92to786...
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