find the sum of all integers from 1 to 500 which are multiples of 2 or 5
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The numbers which are multiple of 2 as well as 5 are also multiple of 10.So, they form an arithmetic progression starting with 10 and common difference of the progression is 10.
Here,number of the terms of A.P. from 1 to 500 is =(500–10)/10+1=50
So,sum=50*(2*10+(50–1)*10)/2=12750
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ayush20031110:
2 as well as 5 nahi hai , 2 or 5 hai
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The numbers which are multiple of 2 as well as 5 are also multiple of 10.So, they form an arithmetic progression starting with 10 and common difference of the progression is 10.
Here,number of the terms of A.P. from 1 to 500 is =(500–10)/10+1=50
So,sum=50*(2*10+(50–1)*10)/2=12750
Here,number of the terms of A.P. from 1 to 500 is =(500–10)/10+1=50
So,sum=50*(2*10+(50–1)*10)/2=12750
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