find the sum of all multiples of 7 lie between 500 & 900
Answers
Answered by
23
Answer:-
39900.
Step by step explanation
Hope it helps!
39900.
Step by step explanation
Hope it helps!
Attachments:
Answered by
31
Hii Mate !!
Here is your answer :
Question : Find the sum of all multiples of 7 lie between 500 and 900.
Solution :
Let a be the first term and d be the common difference of the an AP .
Numbers which are lie between 500 and 900 also which are divisible by 7 are : 504 , 511 , 518 , .......... , 896.
Here,
First term. ( a ) = 504
Common difference ( d ) = 511 - 504 = 7 .
And ,
Last term ( Tn ) = 896
a + ( n - 1 ) * d = 896
504 + ( n - 1 ) * 7 = 896
504 + 7n - 7 = 896
7n + 497 = 896
7n = 896 - 497
7n = 399
n = 399/7
n = 57.
Therefore,
Number of terms = 57.
Sn = n /2 × [ 2a + ( n - 1 ) * d ]
S15 = 57/2 × [ 2* 504 + ( 57 - 1 ) * 7 ]
=> 57/2 × ( 1008 + 56 * 7 )
=> 57 / 2 × 1008 + 392
=> 57/2 × 1400
=> 57 × 700
=> 39900.
Hence,
The sum of all multiples of 7 between 500 and 900 is 39900.
Hope it helps you ♥
By Rishi403.
BeBrainly..
Here is your answer :
Question : Find the sum of all multiples of 7 lie between 500 and 900.
Solution :
Let a be the first term and d be the common difference of the an AP .
Numbers which are lie between 500 and 900 also which are divisible by 7 are : 504 , 511 , 518 , .......... , 896.
Here,
First term. ( a ) = 504
Common difference ( d ) = 511 - 504 = 7 .
And ,
Last term ( Tn ) = 896
a + ( n - 1 ) * d = 896
504 + ( n - 1 ) * 7 = 896
504 + 7n - 7 = 896
7n + 497 = 896
7n = 896 - 497
7n = 399
n = 399/7
n = 57.
Therefore,
Number of terms = 57.
Sn = n /2 × [ 2a + ( n - 1 ) * d ]
S15 = 57/2 × [ 2* 504 + ( 57 - 1 ) * 7 ]
=> 57/2 × ( 1008 + 56 * 7 )
=> 57 / 2 × 1008 + 392
=> 57/2 × 1400
=> 57 × 700
=> 39900.
Hence,
The sum of all multiples of 7 between 500 and 900 is 39900.
Hope it helps you ♥
By Rishi403.
BeBrainly..
Similar questions