Question

Find the Sum of all multiples of 7 lying between 100 and1000

Answer 1

Answer:

128

Step-by-step explanation:

The first multiple of 7 = 105

last multiple of 7 = 994

a = 105

tn = 994

d = 7

tn = a + ( n - 1 ) d

994 = 105 + ( n -1 ) 7

994 - 105 = 7n - 7

889 + 7 = 7n

896 = n

7

n = 128

therefore , there are 128 numbers divisible by 7 between 100 to 1000

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