find the sum of all natural nos between 100 and 500 divisible by 8
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104, 112, ..... 496
Tn = a+(n-1)d
496 = 104 + (n-1)8
392 = 8n-8
400 = 8n
n= 50
Sn = n/2 (a+l)
Sn = 25(104 + 496)
Sn = 25(600)
Sn = 3000*5
Sn = 15000
Tn = a+(n-1)d
496 = 104 + (n-1)8
392 = 8n-8
400 = 8n
n= 50
Sn = n/2 (a+l)
Sn = 25(104 + 496)
Sn = 25(600)
Sn = 3000*5
Sn = 15000
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