find the sum of all natural number between 50 and 250 which ate exactly divisible by 6 find t13
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Answered by
7
13∗6=78
78+156+23478+156+234
=78(1+2+3)=78(1+2+3)
=78∗6=78∗6
=468
In essence, the answer to your question is 468.
Hope this helped!
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Answered by
12
For the explaination refer to
pic.
however,
The sum of all natural numbers from 50 &250 which are divisible by 6 is 4950.
we know that,
tn=a+(n-1)d
t13=54+(13-1)6
t13=54+12×6
t13=54+72
t13=126.
hope this helps you ! ! !
pic.
however,
The sum of all natural numbers from 50 &250 which are divisible by 6 is 4950.
we know that,
tn=a+(n-1)d
t13=54+(13-1)6
t13=54+12×6
t13=54+72
t13=126.
hope this helps you ! ! !
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