Question

find the sum of all natural number less than 100 which are divisible by 6

Answer 1

Hey mate !!

Here's the answer !!

This sum can be solved by the method of Arithmetic Progression.

Here the first natural number divisible by 6 would be 6

The last natural number divisible by 6 would be 96.

So a = 6, d = 6, n = ?, l = 96

We now that,

l = a + ( n - 1 ) d

96 = 6 + ( n - 1 ) 6

96 - 6 = ( n - 1 ) 6

90 = ( n - 1 ) 6

90 / 6 = ( n - 1 )

15 = ( n - 1 )

=> n = 15 + 1 = 16

Hence the total number of terms is 16.

Sum of all these numbers can be given as:

Sum = n / 2 ( a + l )

=> Sum = 16 / 2 ( 6 + 96 )

=> Sum = 8 ( 102 )

=> Sum = 816

Hence the sum of all natural numbers divisible by 6 less than 100 is 816.

Hope my answer helped !!

Cheers !!

Answer 2

Sum of all natural number less than 100 which are divisible by 6 will be 816.

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