find the sum of all natural numbers between 100 and 1000 which are divisible by 5
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a=105
an=995
d=5
an=105+(n-1)5=995
=(n-1)5=995-105=890
=(n-1)=890/5=178
n=179
s179=179/2[105+995]
=179/2*1100
=179*550=98450
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Bhasksr:
Thank you mate
thanks for your answer
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