FIND THE SUM OF ALL NATURAL NUMBERS BETWEEN 200 AND 1000 EXACTLY DIVISIBLE BY 6
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68
204,210,......…......996
a=204. d=6. l(an)=996
an=a+(n-1)6
996=204+(n-1)6
792=(n-1)6
n-1=132
n=133
sum of 133 terms
Sn= N/2(a+l)
S133= 133/2 (204+996)
=133/2 (1200)
=66.5 (1200)
S133=79800
a=204. d=6. l(an)=996
an=a+(n-1)6
996=204+(n-1)6
792=(n-1)6
n-1=132
n=133
sum of 133 terms
Sn= N/2(a+l)
S133= 133/2 (204+996)
=133/2 (1200)
=66.5 (1200)
S133=79800
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