Question

Find the sum of all natural numbers between 200and300 which are exactly divisible by six

Answer 1

Answer:

3486

Step-by-step explanation:

the first number will be 204 so we will take

a = 204

d will be 6 d = 6

and the last number will be = 294

so in ap

tn = a+ (n-1)d

294 = 204 + (n-1)6

6n-6 = 90

6n = 84

n = 14

now formula of sum in ap is

sn = n/2(first + last term)

sn = 14/2(204+294)

sn = 7*(498) = 3486

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