Math, asked by rameshrameshhl1972, 7 months ago

Find the sum of all natural numbers between 200and300 which are exactly divisible by six

Answers

Answered by Anonymous
22

Answer:

Answer: The sum of all natural numbers between 200 and 300 which is divisible by 6 is 4032. The formula for sum in Arithmetic Progression is, Therefore, the sum is 4032.

Step-by-step explanation:

Answered by Anonymous
384

Correct Question:

Find the sum of all natural numbers between 200 and 300 which are exactly divisible by six(6).

Required Answer:

The sum of all natural numbers between 200 and 300 which are exactly divisble by 6 is 4032.

Solution:

Given,

Last term, l = 300

Numbers divisible by 6, n = 16 (204, 210, 216, 222, 228, 234, 240, 246, 252, 258, 264, 270, 276, 282, 288, 294, 300)

First term divisible by 6 = 204

Therefore,

a = 204

n = 16

d = 6

By using Formula:

S = \frac{n}{2} (a + l)

S = \frac{16}{2} (204 + 300)

S = 8 × 504

S = 4032

Therefore, the sum of all natural numbers between 200 and 300 which are divisible by 6 = 4032.


Anonymous: Awesome!
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