Find the sum of all natural numbers between 200and300 which are exactly divisible by six
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Answer:
Answer: The sum of all natural numbers between 200 and 300 which is divisible by 6 is 4032. The formula for sum in Arithmetic Progression is, Therefore, the sum is 4032.
Step-by-step explanation:
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☞Correct Question:
Find the sum of all natural numbers between 200 and 300 which are exactly divisible by six(6).
☞Required Answer:
The sum of all natural numbers between 200 and 300 which are exactly divisble by 6 is 4032.
☞Solution:
✩Given,
Last term, l = 300
Numbers divisible by 6, n = 16 (204, 210, 216, 222, 228, 234, 240, 246, 252, 258, 264, 270, 276, 282, 288, 294, 300)
First term divisible by 6 = 204
Therefore,
a = 204
n = 16
d = 6
✩By using Formula:
S = (a + l)
S = (204 + 300)
S = 8 × 504
S = 4032
Therefore, the sum of all natural numbers between 200 and 300 which are divisible by 6 = 4032.
Anonymous:
Awesome!
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