Question

Find the sum of all natural numbers between 300 and 500 that leaves remainder 2 on division by 7.

Answer 1

Answer:

200

Step-by-step explanation:

Answer 2

Answer:numbers are 303,310,317,.......499

So, first term = 303

To find number of terms ,

499 =303 + (n-1)*7

n=29

Applying sum formula , S = (29/2 )* 802 = 11629

Step-by-step explanation: