Question

Find the sum of all natural numbers between300and500

Answer 1

In this question AP is used
a=301
d=1
last term=499
301+(n-1)=499 (n=number of terms)
=n+300=499
=n=499-300=199
sum of all the required numbers=199/2 ×(2×301+199-1)=199/2 ×800=79600
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