find the sum of all natural numbers in between 200 and 300 which are divisible by 3
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0
201,204,207,210..........
Answered by
0
it is a question of AP
the AP of this question will be
201,204,207..............297
here a=201,d=3 Tn=297
then,
Tn= a+(n-1)d
297=201+(n-1)3
96=(n-1)3
32=n-1
n=40
the AP of this question will be
201,204,207..............297
here a=201,d=3 Tn=297
then,
Tn= a+(n-1)d
297=201+(n-1)3
96=(n-1)3
32=n-1
n=40
NishthaThapaMagar1:
no
yes a=201 d=3 an=297 n=?
an=a+(n-1)d
201(n-1)3=297
201+3n-3 =297
3n+198=297
3n=297-198
3n=99
n=99÷3
n=33
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