Question

Find the sum of all natural numbers less than 2000 and divisible by 6.

Answer 1

Answer:

Step-by-step explanation:

2000 when divided by 6 leaves a remainder of 2. So the greatest number less than 2000 which is divisible by 6 is 1998.

So these numbers for an AP with first term 6, common difference 6 and last term 1998

So 1998 = 6 + (n-1)6

6n = 1998

n = 333

So sum of all such numbers= 333/2(6+1998)

= 3,33,666