find the sum of all number between 250 and 1000 which are exactly divisible by 3.
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Answered by
207
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999
This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999
We Know that
l=a+(n-1)d
999=252+(n-1)3
999 - 252 = 3(n - 1)
n=250
We know that
S=n/2(a+l)
=250/2(252+999)
=125*1251
=156375
Hence, the required sum is 156375.(Ans)
Answered by
62
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