Find the sum of all number
divisible by 5 between 70 and 400
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Answer:
15745 or 1.5745×10^4
Step-by-step explanation:
Let's form an A.P. in order to solve the problem
a1 = 70
an = 400
{common difference is 5 because , it's given that the numbers divisible by 5}
d = 5
a2 = a +d
a2 = 70 +5 = 75
an = a+(n-1)d
400 = 70+(n-1)5
400 = 70+5n-5
70+5n-5 = 400
5n = 400 -70 +5
5n = 335
n = 335 /5
n = 67
So, 67 terms (numbers) are divisible by 5 between 70 amd 400
Now, solving the sum
Sn = n/2 {2a+(n-1)d} or
Sn = n/2 (a1 + an)
S67 = 67/2 (70+400)
S67 = 67/2 (470)
S67 = 67×470 /2
S67 = 67×235
S67 = 6.7×2.35×10^3
S67 = 15.745×10^3 = 1.5745×10^4
or
S67 = 15745
So, the sum of all the numbers divisible by 5 between 70 amd 400 is 15745 or 1.5745×10^4
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