find the sum of all numbers between 1000 and 2500 which are divisible by 6
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Answer:
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999We Know that
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999We Know thatl=a+(n-1)d
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999We Know thatl=a+(n-1)d999=252+(n-1)3
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999We Know thatl=a+(n-1)d999=252+(n-1)3999 - 252 = 3(n - 1)
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999We Know thatl=a+(n-1)d999=252+(n-1)3999 - 252 = 3(n - 1)n=250
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999We Know thatl=a+(n-1)d999=252+(n-1)3999 - 252 = 3(n - 1)n=250We know that
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999We Know thatl=a+(n-1)d999=252+(n-1)3999 - 252 = 3(n - 1)n=250We know thatS=n/2(a+l)
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999We Know thatl=a+(n-1)d999=252+(n-1)3999 - 252 = 3(n - 1)n=250We know thatS=n/2(a+l)=250/2(252+999)
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999We Know thatl=a+(n-1)d999=252+(n-1)3999 - 252 = 3(n - 1)n=250We know thatS=n/2(a+l)=250/2(252+999)=125*1251
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999We Know thatl=a+(n-1)d999=252+(n-1)3999 - 252 = 3(n - 1)n=250We know thatS=n/2(a+l)=250/2(252+999)=125*1251=156375
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999We Know thatl=a+(n-1)d999=252+(n-1)3999 - 252 = 3(n - 1)n=250We know thatS=n/2(a+l)=250/2(252+999)=125*1251=156375Hence, the required sum is 156375.
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