find the sum of all odd natural number from 1 to 150
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Answered by
51
1+3+5+7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49+51+53+55+57+59+61+63+65+67+69+71+73+75+77+79+81+83+85+87+89+91+93+95+97+99+101+103+105+107+109+111+113+115+117+119+121+123+125+127+129+131+133+135+137+139+141+143+145+147+149 = 5625
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ashaq1:
u can calculate it by formula n^2
Answered by
57
hi..
A.P. = 1 + 3 + 5 + ...................+ 149
here,
a = 1
d = 2
l = 149
first we will find,
a(n) = 149
a + (n-1)d = 149
1 + (n-1) 2 = 149
n-1 = 148/2
n = 74 + 1 = 75
so,
n = 75
sum of n terms = n/2 [2a + (n-1)d]
![s(75) = \frac{75}{2} (2 \times 1 + 74 \times 2) s(75) = \frac{75}{2} (2 \times 1 + 74 \times 2)](https://tex.z-dn.net/?f=s%2875%29+%3D+%5Cfrac%7B75%7D%7B2%7D+%282+%5Ctimes+1+%2B+74+%5Ctimes+2%29)
![sum = \frac{75}{2} (2 + 148) sum = \frac{75}{2} (2 + 148)](https://tex.z-dn.net/?f=sum+%3D+%5Cfrac%7B75%7D%7B2%7D+%282+%2B+148%29)
![\frac{75}{2} (150) \frac{75}{2} (150)](https://tex.z-dn.net/?f=+%5Cfrac%7B75%7D%7B2%7D+%28150%29)
![75 \times 75 75 \times 75](https://tex.z-dn.net/?f=75+%5Ctimes+75)
![\bold{ \underline{sum = 5625}} \bold{ \underline{sum = 5625}}](https://tex.z-dn.net/?f=+%5Cbold%7B+%5Cunderline%7Bsum+%3D+5625%7D%7D)
A.P. = 1 + 3 + 5 + ...................+ 149
here,
a = 1
d = 2
l = 149
first we will find,
a(n) = 149
a + (n-1)d = 149
1 + (n-1) 2 = 149
n-1 = 148/2
n = 74 + 1 = 75
so,
n = 75
sum of n terms = n/2 [2a + (n-1)d]
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