find the sum of all odd natural number from 1 to 150
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Answered by
51
1+3+5+7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49+51+53+55+57+59+61+63+65+67+69+71+73+75+77+79+81+83+85+87+89+91+93+95+97+99+101+103+105+107+109+111+113+115+117+119+121+123+125+127+129+131+133+135+137+139+141+143+145+147+149 = 5625
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ashaq1:
u can calculate it by formula n^2
Answered by
57
hi..
A.P. = 1 + 3 + 5 + ...................+ 149
here,
a = 1
d = 2
l = 149
first we will find,
a(n) = 149
a + (n-1)d = 149
1 + (n-1) 2 = 149
n-1 = 148/2
n = 74 + 1 = 75
so,
n = 75
sum of n terms = n/2 [2a + (n-1)d]
A.P. = 1 + 3 + 5 + ...................+ 149
here,
a = 1
d = 2
l = 149
first we will find,
a(n) = 149
a + (n-1)d = 149
1 + (n-1) 2 = 149
n-1 = 148/2
n = 74 + 1 = 75
so,
n = 75
sum of n terms = n/2 [2a + (n-1)d]
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