find the sum of all odd number lying between 101 and 200 which are divisible by 3
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Answered by
0
Step-by-step explanation:
ATQ
series will be
105,111,117,123......................195
an=a+(n-1)d
a=105
d=6
an=195
195=105+(n-1)6
195-105=(n-1)6
90=(n-1)6
15+1=n
n=16
sum is
a
sn=n(a+l)/2
=16(105+195)/2
= 8(300)
= 2400
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