Question

Find the sum of all the integers between 100 and 1000 that are divisible by 9​

Answer 1

Answer:

A.P 108,117,126.......999

Step-by-step explanation:

an=a+(n-1) d

999=108+(n-1) 9 999-108=(n-1) 9

891/9=n-1

99+1=n

n=100

so, Sn=n/2[a+an]

=50[108+999]

=50*1107

=55350 ans

I hope you have got it..