Question

Find the sum of all the integers between 58 and 576 which when divided by 16 leaves the remainder 7

Answer 1

a=71

d=16

an=567

an=a+(n-1)d

567=71+(n-1)16

n-1=31

n=32

Sn=n/2 [2a+(n-1)d]

S32 = 32/2[2*71+ (32-1)16]

S32 = 16 * 638

S32=10208