Question

Find the sum of all the integral multiples of 3 between 4 and 97​

Answer 1

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Answer 2

Concept Introduction:

Sum of AP is $S=n/2[2a+(n-1)d]$

Given:

AP : 6,9,12,......,96

To Find:

We have to find the value of, sum of integral multiple of $3$ between $4$ and $97$

Solution:

According to the problem,

$a=6; d=3;n=31$

$S=n/2[2a+(n-1)d]$

$S=31/2[2*6+(31-1)*3]$

$=31/2[12+90]=31*102/2=1581$

Final Answer:

The value of sum of integral multiple of $3$ between $4$ and $97$ is $1581$.

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