find the sum of all the natural number less than 100 which are divisible by 6
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6+12+18+24+30+36+42+48+54+60+66+72+78+84+90+96=816
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The natural numbers less than 100 which are divisible by 6 are 6, 12, 18,........,96.
6, 12, 18,......., 96 are in A.P
So, a=6, d=6, l=96
an= a+(n-1)d
96=6+(n-1)6
90=(n-1)6
15=n-1
n=16
Sn= n÷2(a+l)
Sn= 16÷2(6+96)
Sn=8×102
Sn=816
So, sum of all natural numbers less than 100 divisible by 6 is 816
6, 12, 18,......., 96 are in A.P
So, a=6, d=6, l=96
an= a+(n-1)d
96=6+(n-1)6
90=(n-1)6
15=n-1
n=16
Sn= n÷2(a+l)
Sn= 16÷2(6+96)
Sn=8×102
Sn=816
So, sum of all natural numbers less than 100 divisible by 6 is 816
sunny4678:
good answer
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