Find the sum of all the numbers between 250 to 1000 divisible by 3
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1
Answer:
156375
Step-by-step explanation:
The numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, ......,999
This is an A.P. whose first term a = 252, Common difference, d = 3 and Last term l=999
We Know that
l=a+(n-1)d
999=252+(n-1)3
999 - 252 = 3(n - 1)
n=250
We know that
S=n/2(a+l)
=250/2(252+999)
=125*1251
=156375
Hence, the required sum is 156375.(Ans)
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