Question

Find the sum of all the terms of the series f: (3), (4/13), (44/13^2), (444/13^3), (4444/13^4)...?

Answer 1

just divide each term from 4/13 by4 and then multiply by 9 for eg you can write
4/13 as
$4 \div 9 \times (10 - 1) \div 13$
and then split and then it would be a gp sum