Find the sum of all three digit number which are divisible by 4 and 3 .
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108,120,..……....,996
a=108. d=12. l(an)=996
an=a+(n-1)d
996=108+(n-1)12
888=(n-1)12
n-1=74
n=75
sum of 75 terms
Sn=n/2(a+l)
S75= 75/2 (108+996)
=37.5 (1104)
=41400
a=108. d=12. l(an)=996
an=a+(n-1)d
996=108+(n-1)12
888=(n-1)12
n-1=74
n=75
sum of 75 terms
Sn=n/2(a+l)
S75= 75/2 (108+996)
=37.5 (1104)
=41400
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