Question

find the sum of all three digits number which are divisible by 7 by Arithmetic Progression class 10​

Answer 1

105,112,119,......994

last term = 994

=> a + (n-1)d = 994

=> 105 + (n-1)7 = 994

=> (n-1)7 = 889

=> n - 1 = 127

=> n = 128

$Sn = \frac{128}{2} (105 + 994) \\ \\ = 64 \times 1099 \\ \\ = 70336$

Answer 2

Answer:

70,336

Step-by-step explanation:

Hope u find my answer helpful...