Find the sum of all tree digit numbers divisible by 4 and 3.
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4×3 = 12
hence the no. which divisible by 3 and 4 must be multiple of 12
a= 12
d =12
tn =996
tn = a + (n-1)d
996 = 12 + (n-1)12
996= 12 +12n -12
996= 12n
83=n
sn = n/2 {2a + (n-1) d}
s83 = 83/2 {(2×12 + 82×12
s83 = 83/2 (24 +984)
s83 = 41832
hence the no. which divisible by 3 and 4 must be multiple of 12
a= 12
d =12
tn =996
tn = a + (n-1)d
996 = 12 + (n-1)12
996= 12 +12n -12
996= 12n
83=n
sn = n/2 {2a + (n-1) d}
s83 = 83/2 {(2×12 + 82×12
s83 = 83/2 (24 +984)
s83 = 41832
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