find the sum of all two digit natural numbers which are neither dividible by 2 nor divisible by 3
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Answer:
1223
Step-by-step explanation:
Sum of all 2 -digit number divisible by 3 be Sn
Sn=a+a+d+.....a+(n−1)d
a=12;d=3
First number is 12 and last is 99
So 99=12+(n−1)d==>n=30
HENCE Sn=30×12+29×30×32=360+29×15×3=1665.
The numbers which are divisible by 4 and 3 are 4×3,4×2×3,....,4×8×3
Let Sn1
denote the sum of The numbers which are divisible by 4 and 3
Sn1=4×3+4×2×3......+4×8×3=12(1+2+....+8)=12((9)(8)2)=12(36)=12×36
The sum of numbers divisible by 3 but not by 4 is Sn−Sn1=1665−432=1233.
Answer 1233.
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