Question

Find the sum of all two digit numbers which
when divided by 4, yeild 1 as remainder.​

Answer 1

Answer:

1210

Explanation:

number should be of the form 4k+1

Smallest 2 digit number that gives remainder 1 when divided by 4 ⇒ 13(when k=3) first term of A.P

Largest 2 digit number that gives remainder 1 when divided by 4 ⇒ 97(when k=24) last term of AP

Series: 13,17,21,....97

97=a+(n−1)d

97=13+(n−1)4

89=(n−1)4

(n−1)=21

n=22

Sum of series =

2

n

[first term + last term]

=

2

22

[13+97]

=11×(110)

=1210

Answer 2

Answer:

right answer of this question is

Explanation:

98 is number

9+8=17/4

remainder =1