Find the sum of angles -1, 2, 3, 4, 5 and 6.
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sum of the angles of 123456 360 because these are of angle of two triangles and each triangle has the angle of 180 total sum
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4
Consider a quadrilateral ABCD.
Then, ∠A+∠B+∠C+∠D=360
To prove this, we join A and C, i.e. we draw the diagonal AC.
In △ABC,
∠CAB+∠ABC+∠BCA=180
[Sum of all angles of a triangle is 180
In △ACD,
∠CAD+∠ADC+∠DCA=180
[Sum of all angle of a triangle is 180
Adding (1) and (2), we get,
(∠CAB+∠ABC+∠BCA)+(∠CAD+∠ADC+∠DCA)=180
+180
∠ABC+∠ADC+(CAB+CAD)+(BCA+DCA)=360
∠ABC+∠ADC+∠BAD+∠BCD=360
∠A+∠B+∠C+∠D=360
That is, the sum of all angles of a quadrilateral is 360
o
=4×90
o
, i.e. 4 right angles.
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